This course is an overview of information technology (IT) and introduces students to a variety of IT areas. Course topics include: office applications, basic computer hardware, networking and security, and webpage creation and programming. Problem-based learning
will be used to improve skills such as teamwork, written and oral communication, problem solving, troubleshooting and project management.
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Course Objectives
By the end of the course, successful students will demonstrate that they have acquired some
of the skills they will need to prepare them for the ongoing process of learning about,
evaluating, and using digital information technologies and applications. Specifically, they
will be able to:
1. Demonstrate that they can use a personal computer or mobile device for accessing the
internet and use basic computer applications such as e-mail, Power point, Excel and
common webpage creation tools.
2. Demonstrate that they can use digital technology in research, analysis, and critical
inquiry.
3. Demonstrate an understanding of the concepts of online security and privacy.
4. Demonstrate knowledge of information technologies and digital cultures, both historic
and contemporary, and be aware of the social, ethical and philosophical issues related
to technological development.
5. Demonstrate that they can evaluate and explain the on-going changes in digital
technology and their impacts on society.
6. Demonstrate that they can apply a variety of information technologies to their own
work, demonstrating their competence in researching, creating, and presenting
projects using a variety of digital information tools.
Admission Requirements
Any applicant who meets the minimum entry requirements for admission into the University may be granted admission, the requirements are :
- O’level Result
- Birth Certificate
- Passport Photograph
REGISTRATION PROCESS
To register for any of the available courses take the following steps
- Click on courses on the menu bar or apply now button to pick a course
- After selecting the course, click apply now to add to cart
- View the cart to fill the application form
- Submit the form to go to the payment page
- Complete the payment form and select method of payment and submit.
- You will receive an email letting you know of your registration and your application status
- You will be contacted by one of our admission team member to guide you on the admission.
- After making the payment of application fee admission letter will be sent to your email with fee structure.
- You will need to make payment of at least 70% of the tuition and acceptance fee for you to be granted access to the course applied for.
- After making the payment an email will be sent to your email with access link to your registered course.
- You study online and can come to school every semester for exams.
FEE STRUCTURE
100 level Fee Structure
180,000 Naira tuition fee
10,000 Naira application fee
20,000 Naira acceptance fee
20,000 Naira Examination Fee
30,000 Naira study kit (t-shirt, course guide, workbook, pen, digital material)
Total 260,000 Naira
200 level Transfer Fee structure
180,000 Naira tuition fee
10,000 Naira application fee
20,000 Naira acceptance fee
20,000 Naira Examination Fee
30,000 Naira transfer fee
30,000 Naira study kit (t-shirt, course guide, workbook, pen, digital material)
Total 290,000 Naira
Transfer final year Fee structure
180,000 Naira tuition fee
10,000 Naira application fee
20,000 Naira acceptance fee
20,000 Naira Examination Fee
30,000 Naira transfer fee
20,000 Naira Project supervision fee
60,000 Naira Certificate fee
20,000 Naira convocation fee
30,000 Naira study kit (t-shirt, course guide, workbook, pen, digital material)
Total 390,000 Naira
CURRICULUM
Applications of Differentiation
In this chapter, we will discuss applications of differentiation to curve sketching and extremal problems. For
curve sketching, we need to consider geometric meanings of the first and second order derivatives. For
convenience, some of the concepts and results are given not in their most general forms. Many of the
concepts and results are stated for functions that are differentiable, twice differentiable etc. Below are the
meanings of these terms.
Terminology Let f be a function that is defined on an open interval (a,b). We say that
• f is differentiable on (a,b) if f 0
(x) exists for all x ∈ (a,b);
• f is twice differentiable on (a,b) if f 00(x) exists for all x ∈ (a,b).
Differentiation
4.1 Derivatives
Consider the curve shown Figure 4.1. It is clear from intuition that the “slope” changes as we move along the
curve. At P 0
, the slope is very steep whereas at P, the slope is gentle (in this sentence, slope means a piece of
ground going up or down).
In elementary coordinate geometry, readers have learnt the concept “slope of a line”. It is a number
which measures how steep is the line. For a non-vertical line, its slope is given by.
Exponential and Logarithmic Functions
8.1 Exponential Functions
Definition Let 0 < b , 1. We define expb to be the function from R into R given by
expb(x) = b
x
, x ∈ R.
The function expb is called the exponential function with base b.
Remark
• If x is a rational number, such as x , then b
x
.
√
• If x is an irrational number such as x = 2, to define b
x we use approximations: more precisely we use
limits.
√ Example
To assign a value to 3 2
:
Note that
√
2 = 1.414213562373095 · · ·
√
We may use 31.
to give an approximate value for 3.
Business analysis
Introduction
CRITICAL LITERACY AND COMPOSITION
Cartesian products of real numbers
An alternative interpretation of joining is that allows the application of implicit functions to
be applied to the space spanned by the data.
Consider a scheme R = (n),n ∈ R and two relations x(R) and y(R). First consider the case where
the relations contain every element of the domain, i.e. x.n = y.n = R. Evaluating the
expression: σx.n2+y.n2−a2=0(x × y)
yields all points on a circle of radius a. That is it finds all points which are the solution to the
equation: x
2 + y
2 − a2 = 0
Implicit equations are ‘solved’ by evaluating them at every point in the space. Since the data
does not usually span the entire domain, the implicit function is only evaluated at the data:.
Cartesian products of real numbers
An alternative interpretation of joining is that allows the application of implicit functions to
be applied to the space spanned by the data.
Consider a scheme R = (n),n ∈ R and two relations x(R) and y(R). First consider the case where
the relations contain every element of the domain, i.e. x.n = y.n = R. Evaluating the
expression: σx.n2+y.n2−a2=0(x × y)
yields all points on a circle of radius a. That is it finds all points which are the solution to the
equation: x
2 + y
2 − a2 = 0
Implicit equations are ‘solved’ by evaluating them at every point in the space. Since the data
does not usually span the entire domain, the implicit function is only evaluated at the data:
Natural Join
A ‘natural join’ is a join followed by some selection and projection:
• Perform a join.
• Perform selection so that attributes with the same name must be equal.
• Perform projection to remove duplicated attributes.
Note that there are no attribute ambiguities.
If attributes with the same name are semantically the same, then the natural join is usually
the correct kind of join to use. In addition to the ‘labs’ table, we also have a table listing lab
sessions: